1/w^2-3/w+2=0

Solution for 1/w^2-3/w+2=0 equation:

D( w )

w^2 = 0

w = 0

w^2 = 0

w^2 = 0

1*w^2 = 0 // : 1

w^2 = 0

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

1/(w^2)-(3/w)+2 = 0

1/(w^2)-3*w^-1+2 = 0

w^-2-3*w^-1+2 = 0

t_1 = w^-1

1*t_1^2-3*t_1^1+2 = 0

t_1^2-3*t_1+2 = 0

DELTA = (-3)^2-(1*2*4)

DELTA = 1

DELTA > 0

t_1 = (1^(1/2)+3)/(1*2) or t_1 = (3-1^(1/2))/(1*2)

t_1 = 2 or t_1 = 1

t_1 = 1

w^-1-1 = 0

1*w^-1 = 1 // : 1

w^-1 = 1

-1 < 0

1/(w^1) = 1 // * w^1

1 = 1*w^1 // : 1

1 = w^1

w = 1

t_1 = 2

w^-1-2 = 0

1*w^-1 = 2 // : 1

w^-1 = 2

-1 < 0

1/(w^1) = 2 // * w^1

1 = 2*w^1 // : 2

1/2 = w^1

w = 1/2

w in { 1, 1/2 }